Răspuns :
√12=2√3
deci 2√3-6√3-2√7+4√3+3√4+2√3=2✓3+6+2√7= 2(√3+3-√7)
deci 2√3-6√3-2√7+4√3+3√4+2√3=2✓3+6+2√7= 2(√3+3-√7)
√12-6√3-2√7+4√3+3√4+2√3=
=2√3-6√3-2√7+4√3+3×2+2√3=
=2√3-2√7+6=
= 2(√3-√7+3)
=2√3-6√3-2√7+4√3+3×2+2√3=
=2√3-2√7+6=
= 2(√3-√7+3)