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Ce cantitate de grame si moli de sulf de aluminiu contine 9600g sulf

Răspuns :

Pokju8888
Al2(SO4)3

M=2.27+3.32+12.16=342

342 g Al2(SO4)3 ----------96 g S
X g ------------------------------9600 gS
X=342.9600:96=34200 g Al2(SO4)3

342g----------1mol
34200g-------y moli
y=34200:342=100 moli Al2(SO4)3

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