Răspuns :
100:2=50cm latura MN
50:2=25cm fiecare latura
ON+OM+MN
25+25+50=100 perimetrul
50:2=25cm fiecare latura
ON+OM+MN
25+25+50=100 perimetrul
este vb de ∆OMN
OM=ON( ∆ isoscel)din ipoteza
MN=2×ON
P=ON+MN+OM
P=2×ON+2×ON
100=4×ON
ON=25cm
OM=25cm
MN=50cm
OM=ON( ∆ isoscel)din ipoteza
MN=2×ON
P=ON+MN+OM
P=2×ON+2×ON
100=4×ON
ON=25cm
OM=25cm
MN=50cm