Răspuns :
2,(4)=2*intregi* 4/9=> 22/9a,b i.p cu 3 si 22/9
3a=22b/9=kx=k/322b=9ky=9k/22ma=(x+y)/2=263x+y=263*2x+y=526k/3+9k/22 =526 (aducem la acelasi numitor)22k+27k =3471649k=34716k= 34716/49x=34716/49 /2= 34716/49 *1/2= 17358/49y= 9*34716/49/22= 9*34716/49 *1/22= 9*1578/49= 14202/49
3a=22b/9=kx=k/322b=9ky=9k/22ma=(x+y)/2=263x+y=263*2x+y=526k/3+9k/22 =526 (aducem la acelasi numitor)22k+27k =3471649k=34716k= 34716/49x=34716/49 /2= 34716/49 *1/2= 17358/49y= 9*34716/49/22= 9*34716/49 *1/22= 9*1578/49= 14202/49