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2 unghiuri suplementare sunt egale cu 0,3(6) supra 0,6(3)
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Răspuns :

Olimpicul2005

[tex] \frac{0.3(6)}{0.6(3)} = \frac{ \frac{36 - 3}{90} }{ \frac{63 - 6}{90} } = \frac{33}{90} \times \frac{57}{90} = \\ \frac{11}{30} \times \frac{19}{30} = \frac{209}{900} [/tex]
Nu stiu cum sa fac mai departe
Icecon2005
0,3(6)=(36-3)/90=33/90=11/30
0,6(3)=(63-6)/90=57/90

a/b=11/30/57/90
a/b=11/30:57/90
a/b=11/30×90/57
a/b=33/57
a=33b/57=11b/19

a+b=180
11b/19+b=180
11b+19b=180×19
30b=180×19
b=(180×19):30
b=114°
a+b=180°, b=114⇒a=180- 114=66°

deci ∡a=66°  si ∡b=114°

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