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a fost răspuns

x:y=3 rest 4
x:z= 2
x+y+z=358
afla:(x+2y+z:2)x3+56=?

Răspuns :

Iiiiiiiiii1
X=y•3+4
X=z•2rezulta ca z=x:2rezulta ca z=(y•3+4):2
Inlocuiesti in suma:
Y•3+4+(y•3+4):2+y|•2
6y+8+3y+4+2y=716(358ori2)
11y+12=716
11y=716-12
11y=704
Y=704:11
Y=64
X=64•3+4
X=196
Z=196:2
Z=98
(196+2•64+98:2)•3+56=1123
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