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a)(4m^2-1)x^2+4mx+1=0

Răspuns :

Ovdumi
4m^2 x^2 + 4mx + 1 -x^2=0
(2mx+1)^2 - x^2=0
(2mx+1-x)(2mx+1+x)=0
x(2m-1)+1=0, x1=1/(1-2m)
x(2m+1)+1=0, x2= - 1/(1+2m), m≠1/2, m≠-1/2

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