👤
a fost răspuns

Sa se detrmine a si b:

2a5+3a+a2a=927
1ab+2ab3+ab01=6211

Răspuns :

Eduardstefan99
200 + 10a +5 +30+a+100a+20+a=927
200+5+30+20+112a=927
255+112a=927
112a=927-255
112a=672
a=672:112
a=6
100+10a+b+200+10a+b+1000a+100b+1=6211
100+200+1+1020a+102b=6211
301+1122ab=6211
1122ab=6211-301
1122ab=5910
a+b=5910:1122
a+b=5 rest 300

Alte intrebari