Răspuns :
a+b+c=80
a=b/2
c=a/2+3=b/4+3
b/2+b+b/4+3=80 inmultim ecuatia cu 4 sau aducem la acelasi numitor
2b+4b+b+12=320
7b=320-12
7b=308 b=308/7 b=44
a=b/2=44/2=22
c=b/4+3=44/4 + 3=11+3 c=14
a=b/2
c=a/2+3=b/4+3
b/2+b+b/4+3=80 inmultim ecuatia cu 4 sau aducem la acelasi numitor
2b+4b+b+12=320
7b=320-12
7b=308 b=308/7 b=44
a=b/2=44/2=22
c=b/4+3=44/4 + 3=11+3 c=14
80_3=77 77impartit la 7 =11 +3=14(c)atunci b este 11*4=44 si a este 2*11=22