Ttei frati au impreuna 27 de nuci.In pauza mare Mihai mananca 7 nuci,Ionel mananca 5 nuci iar Alin mananca 6 nuci.Dupa pauza mare fiecare a ramas cu acelasi numar de nuci.Cate nuci avea initial Ionel?
7+5+6=18 nuci mancate 27-18=9 nuci ramase nemancate 9:3=3 avea fiecare in plus 7+3=10 avea Mihai 5+3=8 avea Ionel 6+3=9 avea Alin Raspuns:8 nuci avea Ionel
