Răspuns :
zahar /___/9
orez /___/ total 2400kg
2400:10=240kg orez
240x9=2160kg zahar
2160+240=2400 kg
orez /___/ total 2400kg
2400:10=240kg orez
240x9=2160kg zahar
2160+240=2400 kg
Metoda I(algebrica):
9o=z
o+z=2400
-------------------
o+9o=2400
10o=2400
o=240 kg
z=9*240 = 2160 kg
----------------------------
Verificare 240+2160=2400 kg OK.
-----------------------------------------------------
Met. II prin segmente:
0rez: I--I
zahar: I--I--I--I--I--I--I--I--I--I
------------------------------------
orez+zahar : I--I--I--I--I--I--I--I--I--I--I 10 segmente = 2400 kg ⇒
1 segment, adica orez = 2400: 10 = 240 kg
9 segmente, adica zahar = 9x240 = 2160 kg
9o=z
o+z=2400
-------------------
o+9o=2400
10o=2400
o=240 kg
z=9*240 = 2160 kg
----------------------------
Verificare 240+2160=2400 kg OK.
-----------------------------------------------------
Met. II prin segmente:
0rez: I--I
zahar: I--I--I--I--I--I--I--I--I--I
------------------------------------
orez+zahar : I--I--I--I--I--I--I--I--I--I--I 10 segmente = 2400 kg ⇒
1 segment, adica orez = 2400: 10 = 240 kg
9 segmente, adica zahar = 9x240 = 2160 kg