3) 6 kg.....................4l
x kg......................9l
[tex] \frac{6}{x} = \frac{4}{9} =\ \textgreater \ x= \frac{6x9}{4} =\ \textgreater \ x= 13.5[/tex] kg de portocale necesare
4) 10m.....................6h
8m ......................x h
[tex] \frac{10}{8} = \frac{x}{6} =\ \textgreater \ x= \frac{10x6}{8} =\ \textgreater \ x=7.5[/tex] ore
Sper ca te-am ajutat!!!
