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Pisica1351miau
a fost răspuns

Determinati numerele x,y si z direct proportionale cu numerele 3;4 si 6 stiind ca z-y+x=10

Răspuns :

MichidutamMicuta
x/3=y/4=z/6=k 
x=3k
y=4k
z=6k
z-y+x=10
6k-4k+3k=10
5k=10
k=2
x=6
y=8
z=12

HELP4HELEN
x/3=y/4=z/6= k
=> x=3k, y=4k, z=6k
z-y+x= 10
=> 6k-4k+3k=10
5k=10 => k=10:5= 2

=> x=2•3=6
y=2•4=8
z=2•6=12

baftă!

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