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a fost răspuns

Află nr necunoscute:
a (X+20)÷12+68=78
b (X+282-75)÷2=104
c X×4÷10+101=133

Răspuns :

Dianabaitanup58csf
a) (X+20):12=78-68
(X+20):12=10
X+20=10x12
X+20=120
X=120-20
X=100

b) (X+282-75)=104x2
(X+282-75)=208
X+282=208+75
X+282=283
X=283-282
X=1

c) Xx4:10=133-101
Xx4:10=32
Xx4=32x10
Xx4=320
X=320:4
X=80