Răspuns :
a,b,c-nr.
a+b+c=289
a=b+34
c=b:2
b+34+b+b:2=289
b+b+b:2=289-34
2b+b:2=255 |×2
4b+b=510
5b=510
b=510:5
b=102
a=b+34
a=102+34
a=136
c=b:2
c=102:2
c=51
a+b+c=289
a=b+34
c=b:2
b+34+b+b:2=289
b+b+b:2=289-34
2b+b:2=255 |×2
4b+b=510
5b=510
b=510:5
b=102
a=b+34
a=102+34
a=136
c=b:2
c=102:2
c=51
/___/___/+34 primul nr
/___/___/ al doilea nr
/___/ al treilea nr
Suma=289
289-34=255 suma segmentelor egale
2+2+1=5 seg egale
255:5=51 un segment ( al treilea nr)
51×2+34=102+34=136 ( primul nr)
51×2=102 al doilea nr
V 136+102+51=289
/___/___/ al doilea nr
/___/ al treilea nr
Suma=289
289-34=255 suma segmentelor egale
2+2+1=5 seg egale
255:5=51 un segment ( al treilea nr)
51×2+34=102+34=136 ( primul nr)
51×2=102 al doilea nr
V 136+102+51=289