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[(a x 3 +400)-100}:5=6900 prin metoda mersului invers

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Nico234679ghd
[(a x 3 +400)-100}:5=6900
[(3a+400)-100}:5=6900
(3a+400-100):5=6900
(3a+300):5= 6900
3a+300= 6900×5
3a+300= 34500
3a=34500-300
3a=34200
a=34200:3
a=11400
[(a×3+400)-100]:5=6900
(3a+400)-100=6900×5
(3a+400)-100=34500
3a+400=34500+100
3a+400=34600
3a=34600-400
3a=34200
a=34200:3
a=11400

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