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Seby667
a fost răspuns

Log2 x-1/x+1+ log2(x^2-1)=4?

Răspuns :

Adrianardeleanp5849q
Log2 x-1/x+1+ log2(x^2-1) = log2 (16)
==> (x-1)/(x+1) * x^2-1 = 16
(x-1)*(x-1)*(x+1) / (x+1) = 16

==> (x-1)^2=16
x^2-2x+1=16
x^2-2x-15=0
delta=64

solutiile: x1=5, x2=-3

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