a × b+500=504
a × b = 504 - 500
a × b = 4 ⇒ a ≠ 0
a × ( b + c + 1 ) = 5
a × b + a × c + a = 5
4 + a × c + a = 5
a × ( c + 1) = 5 - 4 = 1
a = 1
c + 1 = 1 ⇒ c = 1 - 1 = 0 ⇒ c = 0
a × b = 4
1 × b = 4 ⇒ b = 4 : 1 ⇒ b = 4
400 + a + a + 400 + b + b + 400 + c + c = 1 812
2 × a + 2 × b + 2 × c = 1 812 - 1 200
2 × ( a + b + c ) = 612
a + b + c = 612 : 2
a + b + c = 306 → suma celor 3 numere pare consecutive
a + ( a + 2) + ( a + 4) = 306
3 x a + 6 = 306
3 x a = 306 - 6
a = 300 : 3
a = 100 → primul numar par
100 + 2= 102 ( b) → al doilea numar par consecutiv
102 + 2 = 104 ( c ) → al treilea numar par consecutiv
Raspuns: a = 100; b = 102 ; c = 104
