Pentru ex.2):Avem x/4 = y/1,4 = z/1,(5) = K
x+y+z=7,(1)
1,(5) = (15-1)/9 = 14/9
7,(1) =(71-7)/9=64/9
x= 4K ; y = 14 K/10 = 7K/2 ; Z=14K/9
X+Y+Z= 4K+7K/2 + 14K/9 =64/9
Se fac amplificarile, 4k cu 18, 7k cu 9 , 64 cu 2
Avem 18*4k + 9*7k+ 2*14k =2*64
72k+63k+28k=128 => k =163/128
x=4*163/128= 163/32
y=14k/10 = 14*163/1280 =1141/640
z=14k/9 = 14*163/9*32 = 1141/144