Răspuns :
a+b+c =130
b=4a
c=2b=8a
a+4a+8a=130 , 13a =130 => a =130:13=10 ani
b=10 x 4 =40 ani
c=40 x 2 =80 ani
10+40+80=130
b=4a
c=2b=8a
a+4a+8a=130 , 13a =130 => a =130:13=10 ani
b=10 x 4 =40 ani
c=40 x 2 =80 ani
10+40+80=130
t=tata, n=nepot, b=bunic
t+n+b=130
t = 4 x f
b = 2 x t
fiul /-----/
tata /------/------/------/------/
bunic /------/------/------/------//------/------/------/------/
total 130
13segmente=130 ani
1segment = 130:13
1 segment=10 ani
fiul =10 ani
tatal = 10x4=40 ani
bunicul = 40 x 2 =80 ani
t+n+b=130
t = 4 x f
b = 2 x t
fiul /-----/
tata /------/------/------/------/
bunic /------/------/------/------//------/------/------/------/
total 130
13segmente=130 ani
1segment = 130:13
1 segment=10 ani
fiul =10 ani
tatal = 10x4=40 ani
bunicul = 40 x 2 =80 ani