x+y-z=1 999
y=3x
x+3x-0=1999
4x=1999+0
4x=1999
x=1999:4
x=499 rest 3
x+3x-1=1999
4x=1999+1
4x=2000
x=2000:4
x=500-solutia problemei
y=3x=3×500=1500
x+3x-2=1999
4x=1999+2
4x=2001
x=2001:4
x=500 rest 1
x+3x-3=1999
4x=1999+3
4x=2002
x=2001:4
x=500 rest 2
x+3x-4=1999
4x=1999+4
4x=2003
x=2001:4
x=500 rest 3
x=500, y=1 500, z=1
Raspunsurile cu rest -nu sunt solutii ale problemei
