Răspuns :
4(x-y+2z)+2(2x+3y-3z)-3(x-2y+2z)=
4x - 4y + 8z + 4x +6y - 6z - 3x + 6y - 6z = 5x + 8y - 4z=
4x - 4y + 8z + 4x +6y - 6z - 3x + 6y - 6z = 5x + 8y - 4z=
4(x-y+2z)+2(2x+3y-3z)-3(x-2y+2z)=
4x-4y+8z+4x+6y-6z-(3x-6y+6z)=
4x-4y+8z+4x+6y-6z-3x+6y-6z=
5x+8y-4z
4x-4y+8z+4x+6y-6z-(3x-6y+6z)=
4x-4y+8z+4x+6y-6z-3x+6y-6z=
5x+8y-4z