Răspuns :
Folosim (k)coeficenta de relatie
a)2a=k×2=>2a=2k
3b=k×3=>3b=3k
4c=k×4=>5c=4k
b) Si sacoti coeficenta de relatie apoi pui b supra a+c
a)2a=k×2=>2a=2k
3b=k×3=>3b=3k
4c=k×4=>5c=4k
b) Si sacoti coeficenta de relatie apoi pui b supra a+c
2a=3b=4c=k
2a+3b+4c=k+k+k
12=3k
k=4
2a=k, a=2
3b=k, b=4/3
4c=k, c=1
b)
a=p x b/100, p=100a/b=200 x 3/4=150%
2a+3b+4c=k+k+k
12=3k
k=4
2a=k, a=2
3b=k, b=4/3
4c=k, c=1
b)
a=p x b/100, p=100a/b=200 x 3/4=150%