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Rmanduantonio
a fost răspuns

2,4×2,4^3×2,4^5×...×2,4^100
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Răspuns :

HawkEyed
2,4×2,4^3×2,4^5×...×2,4^67 =
2,4^(1+3+5+...+67) = 
2,4^ (34 x 34) =
2,4^ 1156 

1 + 3 + 5 + 7 + … + ( 2n – 1 ) = n x n  
Hatty
2,4*2,4³*2,4^5*...*2,4^67=
2,4(1+3+5+...+67)=
2,4(34²)=
2,4*1156

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