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exercitiiul 13
dau 35 pcte!
va rog am nevoie sa folosesc teorema catetei ,teorema inaltimii si teorema lui pitagora


Exercitiiul 13dau 35 Pcteva Rog Am Nevoie Sa Folosesc Teorema Catetei Teorema Inaltimii Si Teorema Lui Pitagora class=

Răspuns :

a)
BC=CD+BD=27+48=75 cm
In ∆ABC dr=>T. In AD² =CD×BD
AD² = 27×48
AD²=1296
AD=√1296
AD =36 cm
In∆ABC dr. T. Cat. AB²= BD ×BC
AB²= 27×75
AB² =2025
AB=√2025
AB=45 cm
In∆ABC dr =>T. P. AB² +AC²=BC²
45² +AC= 75²
AC²= 5625-2025
AC²=3600
AC=√3600
AC=60 cm

b)
In∆ABC dr=>T. Cat AC²= CD×BC
40²= 32×BC
1600= 32×BC
BC= 1600:32
BC=50 cm
BC=CD+BD=>BD= BC-CD=50-32= 18 cm
In ∆ABC dr=>T. Cat AB²=BD×BC
AB²=18×50
AB²=900
AB=√900
AB=30 cm
In∆ABC dr =>T. In AD² =CD×BD
AD²= 32×18
AD²= 576
AD=√576
AD=24 cm