a) BC=CD+BD=27+48=75 cm In ∆ABC dr=>T. In AD² =CD×BD AD² = 27×48 AD²=1296 AD=√1296 AD =36 cm In∆ABC dr. T. Cat. AB²= BD ×BC AB²= 27×75 AB² =2025 AB=√2025 AB=45 cm In∆ABC dr =>T. P. AB² +AC²=BC² 45² +AC= 75² AC²= 5625-2025 AC²=3600 AC=√3600 AC=60 cm
b) In∆ABC dr=>T. Cat AC²= CD×BC 40²= 32×BC 1600= 32×BC BC= 1600:32 BC=50 cm BC=CD+BD=>BD= BC-CD=50-32= 18 cm In ∆ABC dr=>T. Cat AB²=BD×BC AB²=18×50 AB²=900 AB=√900 AB=30 cm In∆ABC dr =>T. In AD² =CD×BD AD²= 32×18 AD²= 576 AD=√576 AD=24 cm