44g CO2................12g C
352g CO2............x = 96g C
n = m/M = 96/12 = 8 moli C
18g H2O................2g H2
90g H2O..............x = 10g H2
n = m/M = 10/2 = 5 moli H2
1 mol CxHy......8 moli C.......5 moli H2
1 mol................x = 8 atomi C....y = 10 atomi H
F.M => C8H10
Izomer - etilbenzen, o-xilen,p-xilen,meta-xilen
5. a) C6H6 + 3Cl2 => C6H6Cl6
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