[tex] \frac{x}{y} = \frac{7}{9} \\ = > 9x = 7y[/tex]
[tex] \frac{x + 8y}{3x + 6y} \\ [/tex]
Amplificam cu 3:
[tex] \frac{3(x + 8y)}{3(3x + 6y)} \\ \frac{3x + 24y}{9x + 18y} [/tex]
Dar 9x = 7y asa ca inlocuim.
[tex] \frac{3x + 24y}{7y + 18y} [/tex]
Mai amplificam o data cu 3:
[tex] \frac{3(3x + 24y)}{3(7y + 18y)} \\ \frac{9x + 72y}{75y} [/tex]
Dar 9x = 7y si inlocuim
[tex] \frac{7y + 72y}{75y} \\ \frac{79y}{75y} \\ \frac{79}{75} [/tex]
Sper ca n-am gresit pe la calcule. Verifica
