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a fost răspuns

efectuati:g) -10x(x+2)+(x-1)(x+3)[5(x-1)-5(x+3)]
h) (x+1)(x-2)[4(x-3)-2(-5+2x)] +2x(x-1)

Răspuns :

Elena509
-10x-20+(x-1)*(x+3)*(5x-5-5x-15)
-10x-20+(x-1)*(x+3)*(-20)
-20x-20+(-20x+20)*(x+3
-10x-20-20x²-60x+20x+60
-50x+40-20x²
-20x²-50x+40
Icecon2005

g) -10x(x+2)+(x-1)(x+3)[5(x-1)-5(x+3)]
=-10x²-20x+(x²+3x-x-3)[(5x-5-5x-15)
=-10x²-20x + (x²+2x-3)(-20)
=-10x²-20x -20x²-40x+60
=-30x² - 60x + 60
= 60- 60x - 30x²

h) (x+1)(x-2)[4(x-3)-2(-5+2x)] +2x(x-1)=
=(x²-2x+x-2)(4x-12+10-4x)+2x²-2x)=
=(x²-x-2)(-2)+2x²-2x
=- 2x² + 2x +4 + 2x²-2x
= 4

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