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LigiaKitty
a fost răspuns

1+2+3+...+32 supra 4+8+12+...+44=2

Răspuns :

(1+2+3+...+32)/(4+8+12+...+44) = 

= 32*33:2/4(1+2+...+11)

=16*33/4*11*12:2

=16*33/4*11*6

= 2

Obs. Am folosit formula lui Gauss 1+2+..+n = n(n+1):2
( 1 + 2 + 3 + .... + 32 ) / ( 4 + 8 + 12 + .. + 44 )=

32 * 32 : 2 / 4 ( 1 + 2 + .. + 11 )

16 * 33 / 4 * 11 * 12 : 2

16 * 33 / 4 * 11 * 6

= 2