(2-3i)x+(4+i)y=10-i
2x-3xi+4y+yi=10-i
2x+4y+(-3x+y)=10-i
[tex] \left \{ {{2x+4y=10} \atop {-3x+y=-1}} \right. [/tex]
[tex] \left \{ {{2x+4y=10} \atop {-12x+4y=-4}} \right.
[/tex]
Scazand cele doua relatii, obtii:
-10x=6
x=6/-10=-3/5
4y=10-2x
y=(10-2x)/4=(10+6/5)/4=56/5*1/4=56/20=28/10
