Răspuns :
Teodor I-----I
Alexandra I-----I+3
Andrei I-----I+6
T+A+An=81
81-3-6=72
72:3=24 un segment
T=1x24=24
A=24+3=27
An=24+6=30
Alexandra I-----I+3
Andrei I-----I+6
T+A+An=81
81-3-6=72
72:3=24 un segment
T=1x24=24
A=24+3=27
An=24+6=30
A |------------|+3
T |------------| } 81 nuci
A |------------|+6
3+6=9
81-9=72 segmente egale
72:3=24 nuci are Teodor
24+ 3 =27 nuci are Alexandra
27+6=33 nuci are Andrei
R:27,24,33
T |------------| } 81 nuci
A |------------|+6
3+6=9
81-9=72 segmente egale
72:3=24 nuci are Teodor
24+ 3 =27 nuci are Alexandra
27+6=33 nuci are Andrei
R:27,24,33