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EuElisa
a fost răspuns

Sa se rezolve ecuatia: (n+1)!(n+1)=6*(n+2)!
(!)= factorial

Răspuns :

n! (n+1)^2=6*n!*(n+1)(n+2)
n+1=6*(n+2)
5n=-11 ????
(n+2)!=(n+1)!(n+2)
(n+1)!(n+1)=6(n+1)!(n+2) impartim ecuatia la (n+1)!
n+1=6(n+2)
n+1=6n+12
6n+12=n+1
6n-n=1-12
5n=-11
n=-11/5 nu e nr natural deci ecuatia nu are solutii

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