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c=401-401×[(2^(3)×3^(2))^5]:(2×3^(2))-(3312:16-2800:16)
Va rog rezolvare detaliata.
Multumesc

Răspuns :

Slavitescudora
c=401-401×[8×3^10]:(2×9)-(207-175)
c=401-401×[8×59049]:18-32
c=401-401×472392:18-32
c=401-189429192:18-32
c=401-10523844-32
c= -10523443-32
c= -10523475