Răspuns :
Fie a,b,c numerele cautate.
a+b+c=369
a:b=4 rest 5 --> a=4b+5 (1)
b:c=7 rest 8 --> b=7c+8 (2)
Din (1) si (2) avem:
a=4(7c+8)+5=28c+37
Inlocuim in prima relatie astfel:
28c+37+7c+8+c=369
36c+45=369
Scadem 45.
36c=324 --> c=9
Daca c=9 --> b=7c+8=7x9+8=63+8=71
a=289
Numerele cautate au valorile:
a=289, b=71, c=9
a+b+c=369
a:b=4 rest 5 --> a=4b+5 (1)
b:c=7 rest 8 --> b=7c+8 (2)
Din (1) si (2) avem:
a=4(7c+8)+5=28c+37
Inlocuim in prima relatie astfel:
28c+37+7c+8+c=369
36c+45=369
Scadem 45.
36c=324 --> c=9
Daca c=9 --> b=7c+8=7x9+8=63+8=71
a=289
Numerele cautate au valorile:
a=289, b=71, c=9
x+y+z=369
x:y=4+5
y:z=7+8
4(7z+8)+5+7z+8+z=369
28z+32+5+7z+8+z=369
36z=369-45
36z=324
z=324:36
z=9
y=7*9+8
y=71
x=4*71+5
x=289
289+71+9=369