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determinati nr de molecule continut de 4 moli acid colhidric,710g de clor si 112 L(c.n.) de hidrogen

Răspuns :

Moonlight01
nr molecule HCl = 4×NA = 4×6,022×10^23 = 2,4088×10^24

n = m/M = 710/71 = 10 moli Cl2

nr molecule Cl2 = 10×6,022×10^23 = 6,022×10^24

n = V/Vm = 112/22,4 = 5 moli H2

nr molecule H2 =5×6,022×10^23 = 3,011×10^24

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