👤
a fost răspuns

Dacă a=3 si b+c=5 calculeaza a) b+c-a b)4(a+1) c)3(a+2)+4(a-1)

Răspuns :

BogdanilaPopDanila
b+c-a=5-3=2
4(a+1)=4(3+1)=16
3(a+2)+4(a-1)=3(3+2)+4(a-1)=15+8=23
a) b + c - a = 5 - 3 = 2
b) 4 ( a + 1 ) = 4 x ( 3 + 1 ) = 4 x 4 = 16
c) 3 ( a + 2 ) + 4 ( a - 1 ) = 3 x ( 3 + 2 ) + 4 x ( 3 - 1 ) = 3 x 5 + 4 x 2 = 15 + 8 = 23

Alte intrebari