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Maria1033
a fost răspuns

aflati nr a din egalitatea 1+2x {3+4x [5+5x (a+8)]+9}=745

Răspuns :

1+2x {3+4x [5+5x (a+8)]+9}=745
2x {3+4x [5+5x (a+8)]+9}=745-1
3+4x [5+5x (a+8)]+9=744:2
4x[5+5x(a+8)]=372-3-9
5+5x(a+8)=360:4
5a+40=90-5
5a=85-40
a=45:5
a=9

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