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Andreea678
a fost răspuns

Calculeaza:

a) 1 supra 2 + 1 supra 3
b) 2 supra 3 + 3 supra 4
c) 1 supra 4 + 5 supra 6
d) 5 supra 6 + 7 supra 9
e) 1 supra 18 + 1 supra 12
f) 1 supra 3 * 7 la puterea 2 + 1 supra 7 * 3 la puterea 2 + 1 supra 3 la puterea 2 * 7 la puterea 2
g) 1 supra 5 + 1 supra 5 la puterea 2 + 1 supra 5 la puterea 3

Dau coroana


Răspuns :

Voden

Bună!

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[tex]a) ^{3)} \frac{1}{2}+^{2)} \frac{1}{3} =\frac{5}{6}[/tex]

[tex]b) ^{4)} \frac{2}{3}+^{3)} \frac{3}{4} =\frac{17}{12}[/tex]

[tex]c) ^{3)} \frac{1}{4}+^{2)} \frac{5}{6} = \frac{13}{12}[/tex]

[tex]d) ^{3)} \frac{5}{6} +^{2)} \frac{7}{9} =\frac{29}{18}[/tex]

[tex]e) ^{2)} \frac{1}{18}+^{3)} \frac{1}{12} =\frac{5}{36}[/tex]

[tex]f) \frac{1}{3} *7^{2} +\frac{1}{7} *3^{2} +\frac{1}{3^{2} } *7^{2} =[/tex]

[tex]=^{21)} \frac{49}{3}+^{9)} \frac{9}{7}+^{7)} \frac{49}{9} =[/tex]

[tex]=\frac{1029+81+343}{63} =\frac{1453}{63}[/tex]

[tex]g) \frac{1}{5} +\frac{1}{5^{2} }+\frac{1}{5^{3} } =[/tex]

[tex]=^{25)} \frac{1}{5} +^{5)} \frac{1}{25} +\frac{1}{125} =[/tex]

[tex]=\frac{25+5+1}{125} =\frac{31}{125}[/tex]