a-un numar
b-al 2 lea numar
a/4+5=b/3+7
a+b=113
Din a 2 a ecuatie vom scoate a=113-b
Inlocuim in prima: (113-b)/4+5=b/3+7
Aducem la acelasi numitor comun:12
3(113-b)+60=4b+84
339-3b+60=4b+84
339+60-84=7b
7b=315
b=45
a=113-45
a=68
Verificam
a+b=113
45+68=113
