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Andreea678
a fost răspuns

Calculati:

a) (5 supra 6 + 1 5 supra 8) : (1 supra 2) la puterea 2 - 9 1 supra 3
b) [(3 - 2 3 supra 7) * 3 1 supra 2 - 3 supra 21 - 15 supra 35] * 1 1 supra 5

Dau coroana


Răspuns :

[tex]a)( \frac{5}{6} + 1 \frac{5}{8} ) \div ( { \frac{1}{2} })^{2} - 9 \frac{1}{3} [/tex]

[tex] = ( \frac{5}{6} + \frac{13}{8} ) \div \frac{1}{4} - \frac{28}{3} [/tex]

[tex] = ( \frac{40}{48} + \frac{78}{48} ) \times 4 - \frac{28}{3} [/tex]

[tex] = \frac{118}{48} \times 4 - \frac{28}{3} [/tex]

[tex] = \frac{118}{12} - \frac{28}{3} [/tex]

[tex] = \frac{118}{12} - \frac{112}{12} [/tex]

[tex] = \frac{6}{12} [/tex]

[tex] = \frac{1}{2} [/tex]

[tex]b)[(3 - 2 \frac{3}{7} ) \times 3 \frac{1}{2} - \frac{3}{21} - \frac{15}{35} ] \times \frac{11}{5} [/tex]

[tex] = [(3 - \frac{17}{7} )] \times \frac{7}{2} - \frac{1}{7} - \frac{3}{7} ] \times \frac{11}{5} [/tex]

[tex] = [( \frac{21}{7} - \frac{17}{7}) \times \frac{7}{2} + \frac{2}{7} ] \times \frac{11}{5} [/tex]

[tex] = ( \frac{4}{7} \times \frac{7}{2} + \frac{2}{7} ) \times \frac{11}{5} [/tex]

[tex] = ( \frac{4}{2} + \frac{2}{7} ) \times \frac{11}{5} [/tex]

[tex] = ( \frac{28}{7} + \frac{4}{7} ) \times \frac{11}{5} [/tex]

[tex] = \frac{32}{7} \times \frac{11}{5} [/tex]

[tex] = \frac{352}{35} [/tex]