Răspuns :
/___/___/___/ primul nr
/___/ al doilea nr
/___/___/ al treilea nr
Total246
3+1+2=6 parti egale
246:6=41 ( un segment) al doilea nr
41×3=123 primul nr
41×2=82 al treilea nr
V 123+41+82=246
/___/ al doilea nr
/___/___/ al treilea nr
Total246
3+1+2=6 parti egale
246:6=41 ( un segment) al doilea nr
41×3=123 primul nr
41×2=82 al treilea nr
V 123+41+82=246
a + b + c = 246
a = 3×b
c = (a+b) : 2
a /-----/-----/-----/
b /-----/
c /-----/-----/
avem 6 segmente egale = 246
246 : 6 = 41 (valoarea unui segment egal)
a = 3 × 41 = 123
b = 41
c = 2 × 41 = 82
Verificam:
123 + 41 + 82 = 246
a = 3×b
c = (a+b) : 2
a /-----/-----/-----/
b /-----/
c /-----/-----/
avem 6 segmente egale = 246
246 : 6 = 41 (valoarea unui segment egal)
a = 3 × 41 = 123
b = 41
c = 2 × 41 = 82
Verificam:
123 + 41 + 82 = 246