Răspuns :
pV= nRT\
-calculez moliO2
3x32,8=nx0,082x(27+273)---> n= 4mol O2
-calculez moliO2 consumati in reactia cu fosforul P4, M= 124g/mol
n,P4=12,4g/124g/mol= 0,1mol
1mol....5mol
P4 + 5O2---> 2P2O5
-0,1mol....x= 0,5molO2----> RAMAN 4-0,5= 3,5molO2
-calculez presiunea cu acesti moli
px32.8= 3,5x0,082x300----> p=2,625 at
-calculez moli O2 consumati in reactia cu S, M= 32g/mol
n,S= 32g/32g/mol= 1 mol
S+ O2---> SO2-----> rezulta ca 1molS reactioneaza cu 1 molO2---> RAMAN 2,5molO2
px32,8= 2,5x0,082x300---> p=1,875 at
-V,total gaze= 2,5molO2+1molSo2= 3,5mol
V= nxVm= 3,5molx22,4 l/mol=78,4 l in conditii normale
-calculez masa C ce reactioneaza cu 2,5molO2
1mol 1mol
C + O2---> CO2
12g............1mol
x.................2,5mol.....................calculeaza x !!!!!!
-calculez moliO2
3x32,8=nx0,082x(27+273)---> n= 4mol O2
-calculez moliO2 consumati in reactia cu fosforul P4, M= 124g/mol
n,P4=12,4g/124g/mol= 0,1mol
1mol....5mol
P4 + 5O2---> 2P2O5
-0,1mol....x= 0,5molO2----> RAMAN 4-0,5= 3,5molO2
-calculez presiunea cu acesti moli
px32.8= 3,5x0,082x300----> p=2,625 at
-calculez moli O2 consumati in reactia cu S, M= 32g/mol
n,S= 32g/32g/mol= 1 mol
S+ O2---> SO2-----> rezulta ca 1molS reactioneaza cu 1 molO2---> RAMAN 2,5molO2
px32,8= 2,5x0,082x300---> p=1,875 at
-V,total gaze= 2,5molO2+1molSo2= 3,5mol
V= nxVm= 3,5molx22,4 l/mol=78,4 l in conditii normale
-calculez masa C ce reactioneaza cu 2,5molO2
1mol 1mol
C + O2---> CO2
12g............1mol
x.................2,5mol.....................calculeaza x !!!!!!