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Descompuneti in factori, scotand factorul comun :
c) (x-4)*(3x+7)-(x-4)*(4x+2)+3*(x-4)=......
d) (2x+1) la puterea 2 - (3x-2)*(2x+1)+3x*(2x+1)=........

Răspuns :

Iakabcristina2
c) (x-4)(3x+7-4x-2+3)=(x-4)(-x+8)
d) (2x+1)(2x+1-3x+2+3x)=(2x+1)(2x+3)
Triunghiu

c) (x-4)*(3x+7)-(x-4)*(4x+2)+3*(x-4)=

(x-4)×[(3x+7)- (4x+2)+3]=

(x-4)×( - x+8)

d) (2x+1) ² - (3x-2)*(2x+1)+3x*(2x+1)=

(2x+1)×[(2x-1) - (3x-2) + 3x]=

(2x+1)(2x+3)

Sper că te-am ajutat!

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