Răspuns :
a) (3^22)/(2^33) = (3^2)^11 / (2^3)^11 = 9^11/8^11 = (9/8)^11 >1
b) (2^20) /(3^12) = (2^5)^4 / (3^3)^4= 32^4/27^4 = (32/27)^4 >1
c) (5^14)/(3^21) = (5^2)^7 /(3^3)^7 = 25^7/27^7 = (25/27)^7 <1
b) (2^20) /(3^12) = (2^5)^4 / (3^3)^4= 32^4/27^4 = (32/27)^4 >1
c) (5^14)/(3^21) = (5^2)^7 /(3^3)^7 = 25^7/27^7 = (25/27)^7 <1
3²²/2³³ = 3²⁾¹¹/2³⁾¹¹ = 9¹¹/8¹¹ supraunitara
2²⁰/3¹² = 2⁵⁾⁴/3³⁾⁴ = 32⁴/27⁴ supraunitara
5¹⁴/3²¹ = 5²⁾⁷/3³⁾⁷ = 25⁷/27⁷ subunitara
2²⁰/3¹² = 2⁵⁾⁴/3³⁾⁴ = 32⁴/27⁴ supraunitara
5¹⁴/3²¹ = 5²⁾⁷/3³⁾⁷ = 25⁷/27⁷ subunitara