a+b+c+d=120
b=a+2
c=a+4
d=a+6
a+a+2+a+4+a+6=120
4×a+12=120
4×a=120-12
4×a=108
a=108:4
a=27
b=a+2=27+2=29
c=a+4=27+4=31
d=a+6=27+6=33
PROBA
27+29+31+33 (consecutive )=56+64=120 (adevarat )
Rezolvarea cu SEGMENTE =>
a+b+c+d=120
b=a+2
c=a+4
d=a+6
a) |---|
b) |---|+2
c) |---|+4
d) |---|+6 }acolada la toate patru 120
2+4+6=12
120-12=108
Avem 4 segmente egale =>
108:4=27 (a)
27+2=29 (b)
27+4=31 (c)
27+6=33 (d)
PROBA
27+29+31+33 (consecutive )=56+64=120 (adevarat )
