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Leyla111
a fost răspuns

Sa se deter x din egalitatea:65+7×{3+5÷[6-(45÷x+2)]-2-1}=100

Răspuns :

Primăvară2017
65+7×{3+5÷[6-(45÷x+2)]-2-1}=100
7×{3+5÷[6-(45÷x+2)]-2-1}=100-65
7×{3+5÷[6-(45÷x+2)]-2-1}=35
3+5÷[6-(45÷x+2)]-2-1=35:7
3+5÷[6-(45÷x+2)]-2-1=5
3+5÷[6-(45÷x+2)]-2=5+1
3+5÷[6-(45÷x+2)]-2=6
3+5÷[6-(45÷x+2)]=6+2
3+5÷[6-(45÷x+2)]=8
5÷[6-(45÷x+2)]=8-3
5÷[6-(45÷x+2)]=5
6-(45÷x+2)=5÷5
6-(45÷x+2)=1
45÷x+2=6-1
45÷x+2=7
45÷x=7-2
45÷x=5
x=45÷5
x=9

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