Răspuns :
[tex]2x+ \frac{1}{x}+3=0 |x [/tex]
[tex] 2x^{2}+1+3x=0 [/tex]
Δ=9-4*2*1=9-8=1
x1=(-3+1)/4=-2/4=-1/2
x2=(-3-1)/4=-4/4=-1
[tex] 2x^{2}+1+3x=0 [/tex]
Δ=9-4*2*1=9-8=1
x1=(-3+1)/4=-2/4=-1/2
x2=(-3-1)/4=-4/4=-1