Răspuns :
3cutii....149 bomboane
I:a
II:3a
III:3a+9
a+3a+3a+9=149 => 7a +9 = 149 => 7a=140 => a=20
I:a
II:3a
III:3a+9
a+3a+3a+9=149 => 7a +9 = 149 => 7a=140 => a=20
A+b+c=149b
Prima cutie|__|
A doua|__|__|__| 149
A treia|__|__|__|+9
149-9=140
1+3+3=7(sg egale)
140÷7=20(prima cutie)
20*3=60(a doua cutie
60+9=69(a treia cutie)
Prima cutie|__|
A doua|__|__|__| 149
A treia|__|__|__|+9
149-9=140
1+3+3=7(sg egale)
140÷7=20(prima cutie)
20*3=60(a doua cutie
60+9=69(a treia cutie)