Răspuns :
2·5[tex]\dfrac{1}{6}[/tex]=[tex]\dfrac{10n}{6}[/tex]
10[tex]\dfrac{1}{6}[/tex]=[tex]\dfrac{10n}{6}[/tex]
[tex]\dfrac{61}{6}[/tex]=[tex]\dfrac{10n}{6}[/tex]
10n=[tex]\dfrac{61\cdot 6}{6}[/tex]
10n=61
n=[tex]\dfrac{61}{10}[/tex]=6,1
2 * 5intreg 1/6 = 10n/6
5intreg 1/6= (5x6+1)/6= 31/6
2* 31/6 = 10n /6
62/6 = 10n/6
10n = ( 62 x6)/6
10n = 62
n=62/10
5intreg 1/6= (5x6+1)/6= 31/6
2* 31/6 = 10n /6
62/6 = 10n/6
10n = ( 62 x6)/6
10n = 62
n=62/10