m Mg = 10g
Mg + 2HCl => MgCl2 + H2
24g Mg................95g MgCl2
10g Mg................x = 39,583g
n MgCl2 = 39,583/95 = 0,416 moli
MgO + 2HCl => MgCl2 + H2O
40g MgO............95g MgCl2
10g MgO...............x = 23,75g
n MgCl2 = 23,75/95 = 0,25 moli
n MgCl2 total = 0,25+0,416 = 0,666 moli
m MgCl2 total = 63,333g
MMgCl2 = 95g/mol
MMgO = 40g/mol
MMg = 24g/mol